Tentukan pH dari larutan 6 mgram CH3COOH yang terlarut dalam 500 ml air. dengan Ka = 10^-5
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Jawaban:
2.849
Penjelasan:
pH = -log[H]
[H] = akar Ka x Molar
Molar = mol/liter = gr/(Mr x liter)
Molaritas = 6/ 60 x 0,5 = 0.2 M
[H] = akar 10^-6 x 2 = 10^-6 akar 2
pH = -log (10^-3 akar 2)
pH = 3 - log(akar 2)
= 2.849
